18x^2-72x+56=2

Solution for 18x^2-72x+56=2 equation:

18x^2-72x+56=2

We move all terms to the left:

18x^2-72x+56-(2)=0

We add all the numbers together, and all the variables

18x^2-72x+54=0

a = 18; b = -72; c = +54;
Δ = b2-4ac
Δ = -722-4·18·54
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-36}{2*18}=\frac{36}{36}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+36}{2*18}=\frac{108}{36}
=3
$